Question

Please explain me how to graph this :
y= 3^x

Answer 1

You have to look at the behavior of this graph at x approaching +-infinity and x = 0. If you know calculus, you can take the derivatives into account and realize that this function is always increasing and concave up.

at x going to -infinity, the graph approaches 0 but is still positive, so the x-axis is a horizontal asymptote. At x=0, we have y=1. At x approaching +infinity, the graph goes to infinity.

Answer 2

or just get a table of values and plot points but what @tcarroll010 said.

Answer 3

Here's a better graph than the one I drew.

Answer 4

Notic how 3^0 = 1 and 3^1 = 3. You would see that 3^2 = 9

Answer 5

All good now?

Answer 6

@burhan101 ?

Answer 7

how would you use a table of values ?

Answer 8

i am not allowed to use any calculus to solve, it's an advanced function's course and my teacher does not allow :(

Answer 9

You can generate a table of values by selecting various periodic values of x. Just plug in for x = -1000, -100, -10, -1, 0, 1/4, 1/2, 1, 2, 3

That should be enough values to get that curve and then just make a smooth curve for the graph.

Answer 10

okay thanks

Answer 11

let me try this on paper, ill tell you if i get it

Answer 12

You're welcome! Good luck in all your studies and thx for the recognition! @burhan101

Answer 13

Here's a graph with some points

Answer 14

looking at the base of the function, can i assume there will be a point at 1,3 ?

Answer 15

yes, because 3^1 = 3 It will be shown as 1 of the points I drew.

Answer 16

ohh okay !
so if the function was let's say y=5^x there would be a point at 5,1