The exponential decay graph shows the expected depreciation for a new boat, selling for $3,500, over 10 years. Write an exponential function for the graph. Use the function to find the value of the boat after 9.5 years.
@satellite73 @Hero @jim_thompson5910 @hartnn Please help!
Exponential functions have the form: \[ ab^t+c \]Where \(c\) is where it converges (in this case 0), \(a\) is the initial value ($3,500), and \(b\) is the factor by which it decreases after one unit of time.
okay.. so can you help me out on writing the exponential function?
We need to solve for \(b\). It looks like when t is 2, we'll be close to 2000 \[ \begin{array} 2000 &=& 3500b^2 \\ \frac{4}{7} &=& b^2 \\ b &=& \sqrt{\frac{4}{7}} \end{array} \]
Why did you use 3 0's?
Its \(2000\) it cut it off
ok so 200=3500b^2 is my exponential function for the graph to strat with?
2000*
start*
no
Read what I said a few times
what is t? Do I need to find that?
No, t, is the input of the function.
I'm sorry, but I'm really confused :(... So my equation is gonna be what ab^t+c when I plug in the numbers?
Basically
i don't think there is a \(c\) in this
you can use a base of \(\sqrt{\frac{2000}{3500}}=\sqrt{\frac{4}{7}}\) if you like because it looks like it goes from 3500 to 2000 in two years, or else you can use \[3500\times \left(\frac{4}{7}\right)^{\frac{t}{2}}\] since it takes two years to decrease by \(\frac{4}{7}\)
to answer the second part, replace \(t\) by \(9.5\)
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