Question

Find the derivative (No attempt to Simplify!)

Answer 1

\[\sqrt[5]{\frac{ \sin(7x^2\cos(2x^2-5x+7) }{ \sec^3(7x^2-5\sin(2x-1) }}\]

Answer 2

arrggg

Answer 3

lol .. fun. so you can simplify this ;) ... i think

Answer 4

is that sec^3 or sec^2

Answer 5

3 looks like

Answer 6

3. and DON'T attempt to simplify. haha. that would be chaotic.

Answer 7

You don't have enough parentheses in there...

Answer 8

true dat

Answer 9

just a communication thing really tho

Answer 10

Haha. Well wat do u knoe, ur right. fudge.

Answer 11

well, it's a pretty important communication thing, depending on where the missing parentheses go!

Answer 12

agreed.

Answer 13

\[\sqrt[5]{\frac{ \sin(7x^2\cos(2x^2-5x+7)) }{ \sec^3(7x^2-5\sin(2x-1)) }}\]

Answer 14

...what now?

Answer 15

I'm pretty sure the answer is 7 ;-)

Answer 16

why not you ask in a different question thing? this getting a bit full

Answer 17

Nuts, looks like it isn't 7 after all! http://www.wolframalpha.com/input/?i=differentiate+%28sin%287x%5E2*cos%282x%5E2-5x%2B7%29%29%2Fsec%5E3%287x%5E2-5*sin%282x-1%29%29%29%5E%281%2F5%29

Answer 18

......... make sure you wrote it out correctly. that looks uncharacteristically ugly for math.

Answer 19

I would of used logrithmic differentiation for this instead of what wolfram did..