Question

Consider the curve defined by
-8x^2 +5xy+y^3=149. Write an equation for the line tangent to the curve at the point (4, -1)

Answer 1

slope of line tangent to a curve is got by differentiating the curve

Answer 2

and substitute (4,-1) in it

Answer 3

then use slope pont form

Answer 4

would you differentiate the curve with dy/dx?

Answer 5

why dont u try that yourself,,it isnt a hard task ...i will check ur answer

Answer 6

I got dy/dx= (16x+5y)/(5x+3y)

Answer 7

it is dy/dx=16x-5y/(5x+3y^2)

Answer 8

now substitute (4,-1) to get slope at that point

Answer 9

oh ok i see where i messed up

Answer 10

equation of tangent will be

y+1=m(x-4)

where m is slope at the point

Answer 11

got it?

Answer 12

i got 3 for the slope and i think i understand the rest thank you

Answer 13

you are welcome