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Mathematics 20 Online
OpenStudy (anonymous):

f(x)= 2x / (x-1)^2 find f'(x) and f''(x)

OpenStudy (hba):

Can you diffrentiate it ?

OpenStudy (anonymous):

but i'm not so sure of the f"(x) @hba

OpenStudy (anonymous):

is this correct? i'm not so sure of my answer @hba f ' (x) = -2x-2 / (x-1)^3

OpenStudy (hba):

So f'(x)=-2(x+1)/(x-1)^3 Now diffrentiate it again :)

OpenStudy (hba):

Yes that is correct @alyannahere Now diffrentiate it again And you will get f''(x)

OpenStudy (anonymous):

i'm not so sure how to do that is it -2x / 3(x-1)^2 ?

OpenStudy (anonymous):

@alyannahere u know Quotient Rule

OpenStudy (anonymous):

i think so. divide up by down ?

OpenStudy (anonymous):

what i did is (-2x-2) X (x-1)^3 @Yahoo!

OpenStudy (anonymous):

then i'm not so sure how to continue

OpenStudy (anonymous):

f ' (x) = -2x-2 / (x-1)^3

OpenStudy (anonymous):

For f''(x) ..Differentiate f'(x)

OpenStudy (anonymous):

Using Quotient rule

OpenStudy (anonymous):

is it (2x-6) / (x-1)^6 ? @Yahoo!

OpenStudy (anonymous):

f ' (x) = -2x-2 / (x-1)^3 right?

OpenStudy (anonymous):

yup. how do i make that f"(x)

OpenStudy (amoodarya):

look at this file

OpenStudy (anonymous):

hi @amoodarya how did you get 4(x+2) / (x-1)^4

OpenStudy (hba):

Good work @amoodarya ,You are right :)

OpenStudy (anonymous):

oh i got it !!! careless mistake. thanks so much guys !!!

OpenStudy (hba):

Welcome :)

OpenStudy (amoodarya):

look 2 file

OpenStudy (hba):

Good use of wolfram alpha.

OpenStudy (amoodarya):

http://www.wolframalpha.com/widgets/gallery/ you can use it also have step by step

OpenStudy (hba):

No thanks.

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