Mathematics
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OpenStudy (anonymous):
f(x)= 2x / (x-1)^2
find f'(x) and f''(x)
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OpenStudy (hba):
Can you diffrentiate it ?
OpenStudy (anonymous):
but i'm not so sure of the f"(x) @hba
OpenStudy (anonymous):
is this correct? i'm not so sure of my answer @hba
f ' (x) = -2x-2 / (x-1)^3
OpenStudy (hba):
So
f'(x)=-2(x+1)/(x-1)^3
Now diffrentiate it again :)
OpenStudy (hba):
Yes that is correct @alyannahere
Now diffrentiate it again
And you will get
f''(x)
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OpenStudy (anonymous):
i'm not so sure how to do that
is it -2x / 3(x-1)^2 ?
OpenStudy (anonymous):
@alyannahere u know Quotient Rule
OpenStudy (anonymous):
i think so. divide up by down ?
OpenStudy (anonymous):
what i did is (-2x-2) X (x-1)^3 @Yahoo!
OpenStudy (anonymous):
then i'm not so sure how to continue
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OpenStudy (anonymous):
f ' (x) = -2x-2 / (x-1)^3
OpenStudy (anonymous):
For f''(x) ..Differentiate f'(x)
OpenStudy (anonymous):
Using Quotient rule
OpenStudy (anonymous):
is it (2x-6) / (x-1)^6 ? @Yahoo!
OpenStudy (anonymous):
f ' (x) = -2x-2 / (x-1)^3 right?
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OpenStudy (anonymous):
yup. how do i make that f"(x)
OpenStudy (amoodarya):
look at this file
OpenStudy (anonymous):
hi @amoodarya how did you get 4(x+2) / (x-1)^4
OpenStudy (hba):
Good work @amoodarya ,You are right :)
OpenStudy (anonymous):
oh i got it !!! careless mistake. thanks so much guys !!!
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OpenStudy (hba):
Welcome :)
OpenStudy (amoodarya):
look 2 file
OpenStudy (hba):
Good use of wolfram alpha.
OpenStudy (hba):
No thanks.