Question

what is the square root of x^2/5

Answer 1

Think of x^(2/5) as [x^(1/5)]^2

Then you have the + and - square root of that:

+- x^(1/5)

Answer 2

So you have:\[\sqrt{\frac{ x^2 }{ 5 }}\]You can split up:\[\frac{ \sqrt{x^2} }{ \sqrt{5} }\]

Answer 3

Are you looking for the square root of:

x^(2/5)

or

(x^2)/5

?

Answer 4

the 2/5 is the exponent tho?

Answer 5

its the first one :)

Answer 6

If that is the case, then I stick with my first post.

Answer 7

All good now?

Answer 8

Well, apparently, you have x^(2/5). You might consider writing it that way yourself to avoid misunderstanding... ;)

\[x^{\frac{ 2 }{ 5 }}=\sqrt[5]{x^2}=(\sqrt[5]{x})^2\]Take your pick!

Answer 9

if you need the square root of x^(2/5) there is more to do:

1. with exponents only:\[(x^{\frac{ 2 }{ 5 }})^{\frac{ 1 }{ 2 }}=x^{\frac{ 1 }{ 5 }}=\sqrt[5]{x}\]
2. with the result of my last calculation:\[\sqrt{(\sqrt[5]{x})^2 }=\sqrt[5]{x}\]

So the answer is the 5th root of x.