optimization calculus problem help.
Show that among all rectangles with 8-m perimeter, the one that is largest is a square.
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OpenStudy (anonymous):
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let perimeter = 2x + 2y = 8
maximize perimeter (take derivative of it)
set it = 0
OpenStudy (anonymous):
the derivative of it would be 2+2=0
OpenStudy (anonymous):
do you mean the one that is the largest area?
OpenStudy (anonymous):
yeah largest area
OpenStudy (anonymous):
if thats what you mean you have to maximize the area equation A = xy
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OpenStudy (anonymous):
where 2x + 2y = 8, so
2y = 8 - 2x
y = 4 - x
A = x*y
A = x (4 - x)
maximize this one
OpenStudy (anonymous):
4-2x=0
OpenStudy (anonymous):
x=2
OpenStudy (anonymous):
so x = 2 that means the perimeter is
p = 2x + 2y = 8
p = 4 + 2y = 8
solve for y
OpenStudy (anonymous):
y=2
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OpenStudy (anonymous):
perfect!
OpenStudy (anonymous):
how would i write the answer?
OpenStudy (anonymous):
well the work you showed proved that the value of x when the area is maximized is x = 2
then you solved for y using x = 2, and found y = 2
the dimensions of the rectangle is x by y, or 2 by 2, which is a square
that means to maximize the area, the rectangle has to be a square