optimization calculus problem help. Show that among all rectangles with 8-m perimeter, the one that is largest is a square.
|dw:1357670352969:dw| let perimeter = 2x + 2y = 8 maximize perimeter (take derivative of it) set it = 0
the derivative of it would be 2+2=0
do you mean the one that is the largest area?
yeah largest area
if thats what you mean you have to maximize the area equation A = xy
where 2x + 2y = 8, so 2y = 8 - 2x y = 4 - x A = x*y A = x (4 - x) maximize this one
4-2x=0
x=2
so x = 2 that means the perimeter is p = 2x + 2y = 8 p = 4 + 2y = 8 solve for y
y=2
perfect!
how would i write the answer?
well the work you showed proved that the value of x when the area is maximized is x = 2 then you solved for y using x = 2, and found y = 2 the dimensions of the rectangle is x by y, or 2 by 2, which is a square that means to maximize the area, the rectangle has to be a square
thank you so much for your help!
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