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The areas of two similar octagons are 112 in.² and 63 in.². What is the ratio (larger to smaller) of their perimeters? 16/3 4/9 16/9 4/3
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area is a squared unit (m^2), it's 2-dimensional perimeter is just a plain unit(m), it's 1-dimensional the 2-dimensional ratio is 112/63 Then, the 1-dimensional ratio is sqrt(112/63), which is 4/3
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