Question

can some one help me with 6 rational expressions?

Answer 1

\[\frac{3}{ z-4 }+\frac{6 }{ z+3 }\]

Answer 2

what?

Answer 3

@Spartan_Of_Ares, I could have sworn I showed you how to simplify rational expressions.

Answer 4

omggg help me please

Answer 5

i wanted to know if i did this right

Answer 6

spartan

Answer 7

yes

Answer 8

whats the thing is

Answer 9

@jevans17, post your own question

Answer 10

first i got \[\frac{ 3 }{ z-4 }\]\[\frac{ z+18 }{ (z+3)^2 }\] when multiplying

Answer 11

that came out wrong and jevans i have no clue what your talking about

Answer 12

Spartan, where's your teacher?

Answer 13

no my problem is not an equation

Answer 14

my teacher was sick today and we didn't really cover this

Answer 15

Well, you should wait until tomorrow and ask her.

Answer 16

\[\frac{ 3 }{ z-4 }+\frac{ z+18 }{ (z+3)^2 }\] this is how it came out i dont have her again until next tuesday

Answer 17

That's not what you're supposed to do.

Answer 18

ask your own questio jevans

Answer 19

You're supposed to do this:

\[\frac{3}{z-4} \times 1 + \frac{6}{z + 3} \times 1\]
\[\left(\frac{3}{z-4} \times \frac{z+3}{z+3}\right) + \left(\frac{6}{z+3} \times \frac{z-4}{z-4}\right)\]

Answer 20

heroo help me man

Answer 21

help me

Answer 22

@jevans17, where's your Geometry teacher?

Answer 23

i have none i really need help

Answer 24

I can't help fifteen people all at once.

Answer 25

pelase help me rea quick sir please

Answer 26

I still don't understand why you refuse to post your own question

Answer 27

thats my question sir its thee same

Answer 28

\[i got \frac{ 3z+9 }{ z^2-12 }+\frac{ 6z-24 }{ z^2-12 }\]

Answer 29

:{

Answer 30

lol he dumb

Answer 31

@jevans17, go to your own question

Answer 32

hero it is my own question
its the same question

Answer 33

@Spartan_Of_Ares, you got the numerators correct.

Answer 34

on a scale of 1-10 how badly did i do that?

Answer 35

real bacl a 10

Answer 36

F

Answer 37

The denominators need work. See if you can understand this:

\[(z - 4)(z + 3) = z(z + 3) - 4(z + 3) = z^2 + 3z - 4z - 12 = z^2 - z - 12\]

Answer 38

Hero help me pelase i dont have all day

Answer 39

GTFO!!

Answer 40

\[\space\space\space\space\space(z - 4)(z + 3)
\\= z(z + 3) - 4(z + 3)
\\= z^2 + 3z - 4z - 12
\\= z^2 - z - 12\]

Answer 41

Ares shut the f up and learn to multiply

Answer 42

@Spartan_Of_Ares, do you understand what I am posting?

Answer 43

yes i just didnt understand how you were getting a trinomial but that make sense

Answer 44

Hero how do i get someone else who can help me cause your no help at all

Answer 45

post your own question!

Answer 46

@jevans17, I refuse to help someone who infiltrates someone else's question.

Answer 47

I posted my own

Answer 48

ok so now ill have \[\frac{ 9z-15 }{z^2-z-12 }\] right?

Answer 49

@jevans17 Please refrain from posting your question inside someone else's question. That is just plain Disrespectful.

Answer 50

did i combine it right?

Answer 51

is that my final answer?

Answer 52

(っ⌒‿⌒)っ is it the final answer?(っ⌒‿⌒)っ

Answer 53

It is correct. That's why I gave you a medal

Answer 54

im sad its not an answer could it be

Answer 55

Yes, that is it bro. Remember:

(z - 4)(z + 3) = z^2 - z - 12

Answer 56

ok thanks for the help

Answer 57

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Answer 58

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