Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Find all zeros. Show synthetic division or factor. f(x) = x^4 + 2x^3 + x^2 - 4

OpenStudy (anonymous):

@jim_thompson5910 ?

jimthompson5910 (jim_thompson5910):

First list all the possible factors of 4, what are they?

OpenStudy (anonymous):

1,2,4?

jimthompson5910 (jim_thompson5910):

-1,-2,-4 is also included as well

jimthompson5910 (jim_thompson5910):

so those are your possible rational roots

OpenStudy (anonymous):

But are those the zeros? How would it be shown in synthetic division?

jimthompson5910 (jim_thompson5910):

say we want to test x = -1 as a root (ie see if it's a root) then this is what we get for our synthetic division table -1 | 1 2 1 0 -4 | -1 -1 0 0 -------------------------------------------------- 1 1 0 0 -4 Notice how the last value in the last row is -4 This means that x = -1 is NOT a root

OpenStudy (anonymous):

Okay makes sense. And a root is refered to as a zero correct? What WOULD be the roots?

jimthompson5910 (jim_thompson5910):

You would repeat this table, but do it for x = 1, x = 2, x = 4, etc for all the possible roots

jimthompson5910 (jim_thompson5910):

if you get 0 as the last value in the last row, then that value is a root or zero

jimthompson5910 (jim_thompson5910):

and yes, root = zero of a function

OpenStudy (anonymous):

Okay let me test.

OpenStudy (anonymous):

It's not -2 correct?

jimthompson5910 (jim_thompson5910):

what value did you get in the last row

OpenStudy (anonymous):

-8 if I did it right.

jimthompson5910 (jim_thompson5910):

you didn't, you went wrong somewhere

OpenStudy (anonymous):

Let me try again.

jimthompson5910 (jim_thompson5910):

alright

OpenStudy (anonymous):

Oh okay found my mistake. It is -2. What's the next step?

jimthompson5910 (jim_thompson5910):

you should have gotten this -2 | 1 2 1 0 -4 | -2 0 -2 4 -------------------------------------------------- 1 0 1 -2 0 did you get this?

OpenStudy (anonymous):

Yes I did.

jimthompson5910 (jim_thompson5910):

ok so the last row 1 0 1 -2 0 translates to x^3 + 0x^2 + 1x - 2 remainder 0 which turns into x^3 + x - 2

jimthompson5910 (jim_thompson5910):

now you repeat the whole process we did above to find the possible roots and check them

jimthompson5910 (jim_thompson5910):

to save time, the possible roots of x^3 + x - 2 are: -1, 1, -2, 2

jimthompson5910 (jim_thompson5910):

possible rational roots*

OpenStudy (anonymous):

Thanks! So with the x^3 + x - 2 equation I redo the synthetic division process? Like this:|dw:1357696606227:dw| What am I missing?

jimthompson5910 (jim_thompson5910):

it should be -2 | 1 0 1 -2 | -2 ---------------------------------------- 1 I'll let you finish the table

OpenStudy (anonymous):

I think I messed up.|dw:1357696782818:dw|

jimthompson5910 (jim_thompson5910):

you did it right, i got this -2 | 1 0 1 -2 | -2 4 -10 ---------------------------------------- 1 -2 5 -12 which is exactly what you have

jimthompson5910 (jim_thompson5910):

so -2 is NOT a root to x^3 + x - 2

OpenStudy (anonymous):

Oh okay. :)

OpenStudy (anonymous):

So do I test 2, 1, -1 now?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

Okay so the correct root is 1.

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

what table do you get for x = 1

OpenStudy (anonymous):

Next?

jimthompson5910 (jim_thompson5910):

when you did synthetic division, what table did you get for x = 1

OpenStudy (anonymous):

|dw:1357697238100:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!