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Chemistry 15 Online
OpenStudy (anonymous):

(This was a lab we did today) 5ml of an unknown weak acid is titrated with 10.8ml of NaOH to reach the endpoint. How do you determine the concentration of hydrogen [H+] in the acid?

OpenStudy (anonymous):

what other information do you need to find the [H+] of an acid?

OpenStudy (anonymous):

did you find out what the unkown weak acid was?

OpenStudy (anonymous):

no, all we have is the volume of the acid and the volume of NaOH needed for the endpoint.and the concentration of it, 1.295mol/L

OpenStudy (anonymous):

the question says use the volume of the base used to reach the endpoint to find the [H+] of the acid

OpenStudy (anonymous):

no molarity of the NaOH solution?

OpenStudy (anonymous):

we had to standardize it. we dissolved 1g of solid NaOH into 250ml of water. Then we had to titrate it and it took 19ml to reach the endpoint.

OpenStudy (anonymous):

Then it says calculate the [NaOH] aq but i dont know if i did it right.

OpenStudy (anonymous):

there are 0.025mol in 1g of NaOH. So does that mean if c=n/v then 0.025mol/0.019L= 1.315mol/L b/c it took 19 ml of NaOH to bring the acid the endpoint so thats the volume you use to find the concentration of it?

OpenStudy (anonymous):

so it means that the NaOH solution is actually 1.315M NaOH and 19 mL of it

OpenStudy (anonymous):

can you find a way to compare the 5mL and 19 mL solution

OpenStudy (anonymous):

http://www.youtube.com/watch?v=N937jaLljVg may help =]

OpenStudy (anonymous):

okay i'll check it out, thanks for your help:)

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