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Mathematics 19 Online
OpenStudy (anonymous):

How do I solve sin(x)=3 and sin(x)=1

OpenStudy (nottim):

what do you mean? separately?

OpenStudy (anonymous):

Yeah. from 0-2pi I understand that the inverse sine of 1 is 90. But since to domain of sine is from -1 to 1, how do I solve sin(x)=3?

OpenStudy (nottim):

This is in RADians?

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

so it would actually be pi/2 , not 90, right?

OpenStudy (nottim):

grd 12 advd functions right? I can't remember.

OpenStudy (nottim):

did this have a diagram of some sort? A unit circle?

OpenStudy (anonymous):

No, the original question was: find all real solutions to the equation sin^2(x)-4sin(x)+3=0 for 0<x<2pi. and I solved that down to sin(x)=3 and sin(x)=1. Don't know what to do with that sin(x)=3.

hartnn (hartnn):

maximum value of sin x =1, it can never =3

OpenStudy (anonymous):

so the only real answer would be pi/2?

hartnn (hartnn):

so, you take only sin x=1 yes!

OpenStudy (anonymous):

THANK YOU BOTH!

hartnn (hartnn):

welcome ^_^

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