Question

PLEASE HELP: SIMPLE HARMONIC MOTION

A 0.77 kg object is attached to one end of a spring hanging vertically from a stand. The object is pushed upward 0.14m from the equilibrium position and released, causing the object to oscillate in simple harmonic motion with a frequency of 0.769Hz. Determine the period of the motion, angular frequency, spring constant, Displacement of the object after 0.13s, and Acceleration of the object after 0.13s

Answer 1

Hi
you can find \[\omega \] from this :\[\omega =2(pi)f\] and spring constant from this:\[\omega=\sqrt({k/m})\]

Answer 2

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Answer 3

Probably..It is Already Solved...

Answer 4

this solution is formula based..Explain it