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Precalculus 13 Online
OpenStudy (anonymous):

complex zeros to give the fully factored form : (-3) (x-2i)(x+2i) but this to be finished must have a x in it. Can anyone help me?

OpenStudy (anonymous):

not sure what you mean, you can multiply this out if you like you will get \(-3(x^2+4)\) as a start

OpenStudy (anonymous):

otherwise what you have is fully factored as it is

OpenStudy (whpalmer4):

You have x's in there. Your complex zeros are (x - 2i) = 0 and (x + 2i) = 0, giving x = 2i and x = -2i as the zeros.

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