Factor the following expression:
6(x^2 - 4x + 4)^2 + (x^2 - 4x + 4) -1

So I simplfied it to:

6x^2 + x -1

I use the crisscross method which is REALLY fast and accurate.... but I couldn't find an answer...

Can you tell me a hint? :D

Question

Factor the following expression:
6(x^2 - 4x + 4)^2 + (x^2 - 4x + 4) -1

So I simplfied it to:

6x^2 + x -1

I use the crisscross method which is REALLY fast and accurate.... but I couldn't find an answer...

Can you tell me a hint? :D

anonymous · Answer

Nevermind got it.

anonymous · Answer

Thanks anyways :D

campbell_st · Answer

this is a simple way

let 

$$u = x^2 -4x + 4$$

using this substitution you would get a quadratic 

$$6u^2 + u - 1$$

which can be factored 

once its factored then you can replace u by the original substitution

anonymous · Answer

I get that part
i was stuck on finding the numbers that x to -6 and add to +1

campbell_st · Answer

ok... 

if you have 

$$ax^2 + bx + c$$ 
I always do 

$$a \times c$$

and find the factors that add to b

so 6 x - 1 = -6 

what factors of -6 add to 1

campbell_st · Answer

try 3 ans - 2

anonymous · Answer

so $$[3(x^2-4x+4) -2][2(x^2-4x+4)+3]$$?

anonymous · Answer

Answers say I'm wrong... it says $$(2x^2 - 8x + 9)(3x^2 - 12x + 11)$$

campbell_st · Answer

not quite right... this is the method I use when I have the factors correct... 

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next remove the common factors from each set of brackets

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