By finding a gold nugget,a prospector is said to"strike it rich." If, on any given day, a prospector has probability 1/8 of striking it rich, what is the probability that at least one of the prospectors Al and Barb strike it rich on a day they both mine for gold?
if Al has a probability of 1/8 and so does Barb remember that P(A or B)=P(A)+P(B)−P(A and B)
@binarymimic ok soo.. what then lol
so.. the probability is .125? :P
What did you use for P(A), P(B), and P(A and B) ?
i plugged in 1/8 :)
P(A) is 1/8 P(B) is 1/8 but what did you get for P(A and B) ?
oh 2/8 lol
oh no we cant do that :)
otherwise we would get 1/8 + 1/8 - 2/8, and that = 0
P(A and B) means the probability of both happening at the same time. we would actually multiply 1/8 * 1/8 to get P(A and B)
.015625 +.25= .265625
so that's the answer? =.=
yup .. isn't as pretty as your first answer but .. it is what it is
wait
you didn't subtract
thank you kind sir ^^
it should be P(A) + P(B) - P(A and B) 1/8 + 1/8 - 1/64
.25-.015625=.234375 ok gotcha ;)
you got it :) bye for now
:)
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