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Algebra 18 Online
OpenStudy (anonymous):

What is the smallest integer lager than

OpenStudy (anonymous):

\[\huge(\sqrt{3}+\sqrt{2})^6\]

OpenStudy (jiteshmeghwal9):

Let the integer be x. than \((\sqrt{3}+\sqrt{2})^6<x\)

OpenStudy (jiteshmeghwal9):

First of all solve this inequality than all the values larger than the equation will be x. the smallest integer of x will be ur answer :)

OpenStudy (anonymous):

\[ {x}^{1/6} >\sqrt{3}+\sqrt{2}\]

OpenStudy (anonymous):

\[x^{1/3}>3+2\sqrt{6}+2=5+2\sqrt{6}>9\]

OpenStudy (anonymous):

\[x>\sqrt[3]{9}>\sqrt[3]{8}=2\]

OpenStudy (anonymous):

@jiteshmeghwal9

OpenStudy (jiteshmeghwal9):

ok now wht do u think the value of x is ?

OpenStudy (anonymous):

isn't two the one

OpenStudy (raden):

i think u have to expand of (sqrt(2) + sqrt(3))^6, first..

OpenStudy (anonymous):

\[=(5+2\sqrt{6})^3=125+3(25)2\sqrt{6}+3(5)24+8(\sqrt{6^3})\]

OpenStudy (raden):

yes, = ... + ...*sqrt(6)

OpenStudy (raden):

and finally u just take a smallest integer number of the result above

OpenStudy (raden):

dont forget use ur calculator to get the value of sqrt(6) :)

OpenStudy (anonymous):

\[485+125\sqrt{6}+8\sqrt{6}^3\] \[\sqrt{6}>2\] \[>485+125(2)+8(2^3)=799\]

OpenStudy (raden):

hmmm.. 485 + 3(25)2√(6) + 3(5)24 + 8*(√((6)^3) = 125 + 150√(6) + 360 + 8*6√(6) = 485 + (150+48)√(6) = 485 + 198√(6) = 485 + 484.99 = 969.99

OpenStudy (raden):

so, the smallest integer number than 969.99 is 970

OpenStudy (anonymous):

no calculator is allowed here

OpenStudy (raden):

i think u can determine the value of sqrt(6) without calculator, right ?

OpenStudy (raden):

just remember that : sqrt(4) < sqrt(6) < sqrt(9) 2 < sqrt(6) < 3 so, sqrt(6) = 2.(.......), u can take nearst 2 decimals form

OpenStudy (anonymous):

so 485+125(3)+8(sqrt6)^(3) 485+125(3)+8(3^3)=1076

OpenStudy (raden):

970 is smallest than 1076 :p

OpenStudy (shubhamsrg):

*

OpenStudy (anonymous):

* means

OpenStudy (shubhamsrg):

* means I bookmarked the question. Now whenever there is a post on the topic, I'll get a notification.

OpenStudy (anonymous):

cool so how do I bookmark a question

OpenStudy (anonymous):

do I just post the asteric *

OpenStudy (shubhamsrg):

o.O * was just a symbol of bookmark,I could have made any other comment also over here for the notification thing. I chose *

OpenStudy (anonymous):

485 + 198√(6) Now, I would use NEWTON's METHOD to find its approxmiate value. Let x=198√(6) x^2=198*198*6 x^2=235224 x^2-235224=0 f(x)=0

OpenStudy (anonymous):

I hope u can do it

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