Question

CALLING ALL MATH GENIUSES. I NEED YOUR HELP!

Answer 1

Which of the following is the slope between the two points (2, 3) and (1, 4)?

1

1/3

-1

-1/3

Answer 2

I know that this is fairly easy, but when we learned the lesson, I was sick and I missed a lot of school :( I'm really behind.

Answer 3

For example if you have the points \(\rm (hey, i)\) and \(\rm (hate,math)\), then the slope is:\[\rm \dfrac{math - i}{hate-hey}\]

Answer 4

soo how would we write that with the numbers that I have?

Answer 5

Let \(\rm hey = 2,i=3,hate=1,math=4\) and voila.

Answer 6

hold on a seconddd

Answer 7

Sure.

Answer 8

okay so that we get

4-3
----
1-2

Answer 9

Yeah! Simplify.

Answer 10

1/3

Answer 11

What is \(4-3\)?

Answer 12

1

Answer 13

What is \(1 - 2\)?

Answer 14

-1

Answer 15

What is \(\dfrac{1}{-1}\)?

Answer 16

-1? :|

Answer 17

Right there brah.

Answer 18

What is (1)*(-1)?

Answer 19

:D thank you! Can you please help me w a few more so I can be sure that I understand?

Answer 20

Sure! :-)

Answer 21

Thanks!

It's the same type of question. We have to find the slope between (-3,1) and (3,-6)

Answer 22

Okay, use that formula only.

Answer 23

Now I'm guessing that we're going to set up the equation like:

-3 - 3
-------
1 - -6

Answer 24

Actually, it's done the wrong way. \(-3 - 3\) should be down and \(1-(-6)\) should be up.

Answer 25

Not to confuse you, but I think I should give you a gentle introduction to what a slope is.

Answer 26

Lol! That was actually the way I wrote it the first time but I doubted myself and switched it /:

Answer 27

So the slope is the steepness.

Answer 28

So the line \(\rm omg\) is much more steep and so has more slope.

Answer 29

right

Answer 30

But what exactly is slope? Stare at this:

Answer 31

So the slope is \(\dfrac{2}{1}\).

Answer 32

that's where rise over run comes in?

Answer 33

YUP!

Answer 34

The line has risen \(2\) units and ran \(1\) unit. So \(2/1 = 2\).

Answer 35

But you might not wanna draw a line and see what the rise is... so there's a shortcut.
Look at the diagram again.