Question

12x^2-243

Answer 1

Solving for x?

Answer 2

yes factor

Answer 3

\[12x^2 - 243\]
\[3(4x^2 - 81) = 0\]
dividing both sides by 3:
\[4x^2 - 81 = 0\]
factoring:
\[(2x - 9)(2x + 9) = 0\]
Do you want me to continue or you can pick it up from here?

Answer 4

continue

Answer 5

Now we have to equations:
\[2x - 9 = 0\]
and
\[2x + 9 = 0\]
solving them:
\[2x - 9 = 0\]
\[2x = 9\]
dividing by 2:
\[x = \frac{ 9 }{ 2}\]
the other equation:
\[2x + 9 = 0\]
\[2x = -9\]
dividing by 2:
\[x = -\frac{ 9 }{ 2 }\]

Answer 6

another is:

Answer 7

12X^2-243=0
12x^2=243
x^2=243/12=81/4
x=+9/2
x=-9/2

Answer 8

Yeah it's shorter but he wanted factorization.

Answer 9

i can write another way do you want? ;)

Answer 10

12x^2-243=0
div 12:
x^2-81/4=0
from a^2-b^2=(a+b)(a-b) we have:
x^2-81/4=(x-9/2)(x+9/2)