x^4-81 divided by x-3

Question

anonymous · Answer

using synthetic division

anonymous · Answer

I am not personally smart enough to figure it out, but this site really helped me with this sort of thing: ww.algebrahelp.com/calculators/equation/
Just put your question in there. Today it wasn't working, but I've used it in the past.

anonymous · Answer

okay Thank you!! (:

anonymous · Answer

Let me know if it doesn't work :) and your welcome :)

anonymous · Answer

yeah i don't think its working :(

anonymous · Answer

Ok, I know the site wasn't working today, but if you don't need it right away, you can try again later. Sorry :(

anonymous · Answer

well you an factorize the equation, because you know that 9^2= 81, :$$x ^{4} - 81 = (x ^{2}-9)*(x ^{2}+9)$$ it is a property of factorization-->$$x ^{2}- a ^{2}=(x-a)(x+a)$$..
follow this you can factorize also $$x ^{2}-9 = (x+3)(x-3)$$ and then you can to elimine (x-3) in the denominator and the numerator...

anonymous · Answer

at te end, you have $$\frac{ (x-3)*(x+3)*(x ^{2}+9) }{x-3 }= (x+3)*(x ^{2}+9)$$