Can anyone help? So confused!! a hexagonal tray of vegetables has an area of 450 cm^2. What is the length of each side of the hexagon? Also, what is the area at the bottom in terms of the side length?
Does anyone know how to do this??
@phi can you help?
do you know the formula for the area of a hexagon ?
no I don't
see wikipedia http://en.wikipedia.org/wiki/Hexagon#Regular_hexagon for a formula that gives the area as a function of the length of a side
ok
do you see the formula ?
yes, but it sure looks confusing.
\[ A = \frac{3\sqrt{3}}{2} t^2 \] where t is the length of 1 side
multiply both sides by the reciprocal of 3sqrt(3)/2 to get t^2 by itself
ok
so would I end up with 450 cm^2 times t^2
oh wait, I messed up. nevermind
write down your steps
2/3^3(450cm^2) = 2/3^3(3^3/2)
and don't forget the side call it s^2 (not sure why wiki uses t^2) 2/3^3(450cm^2) = s^2 (the other stuff cancels out) now simplify the left side
\[ \frac{2 \cdot 450}{3 \sqrt{3} } = s^2 \]
900/3^3 = s^2
oops I didnt mean 3^3 I meant 3 sqrt 3
you could divide 3 into 900, right ? and I would multiply top and bottom by sqrt(3) to move the sqrt up top
yeah 3 into 900 is 300
multiply top and bottom by sqrt(3)
1558.8/9
900 * sqrt 3 = 1558.8 and 3 sqrt 3 * sqrt 3 = 9
I would not change the answer to decimals, as that is not an exact answer you should get \[s^2= 100 \sqrt{3} \]
ohh ok
now take the square root of both sides
btw, \[ \sqrt{\sqrt{x}} = \sqrt[4]{x} \]
I think I just confused myself. lol so I would take the square root of 100 sqrt 3?
and s^2 on the other side
10^4√3 ?
yes, and now you can give the decimal approximation \[ s= 10 \sqrt[4]{3} \approx 13.161\]
yay!
btw, could also write it as \[s= 10 \cdot 3^{\frac{1}{4}} \] that is 3 to the 1/4 power
oh ok
Thanks for your help! That made understand it alot better.
made me^
If you could google for the formula, you could have figured it out. divide the hexagon into 6 congruent triangles, and figure out the area of one of the triangles. then multiply by 6 to get the hexagon
oh ok. google just looked real confusing when I first saw the formula, but that makes more sense now.
Join our real-time social learning platform and learn together with your friends!