Question

Find the measure of the largest angle of a triangle with sides of length 27 cm, 35 cm, and 51 cm.

Answer 1

Use Trig ratios, or the Cos and Sin Law.

Answer 2

\[\cos C=\frac{ a^2+b^2-c^2 }{ 2ab }\]
where "a" and "b" correspond with the two shorter sides of the triangle and "c" corresponding with the hypotenuse (ie. longest side of the triangle). Angle C is directly opposite to the hypotenuse, "c", thus will give you the largest angle of the triangle.

Answer 3

http://en.wikipedia.org/wiki/Law_of_sines
http://www.purplemath.com/modules/basirati.htm
http://en.wikipedia.org/wiki/Law_of_cosines

Answer 4

So the equation would be \[CosC= (27^2+35^2-51^2)/(2*27*35)\]

Answer 5

it seems true