2x^2 = 2 + y
what you want?
simply it. would I get like xy=?
I'm trying to do 2sin^2 = 2 + cos but I tried to do the algebraic form first.
you want yx=? are you sure?
well what I really need is 2sin^2 = 2 + cos
your first equation is 2sin^2 = 2 + cos ??!
it is very different because very relations between sin and cos are identifed
yeah but i was trying to see if it worked cause for other problems if I work it the algebraic way it will work with the precalculus.
:)) very funny
hey that's what my teacher told us to do if we had any problems! :P
So can you help me with this problem?
probably your teacher mentioned to an especial kind of problems.
nope
for example 1=sin^2 +cos^2 and you can get 2sin^2 = 2 + cos 2sin^2 = (1) +1 + cos 2sin^2 = (sin^2 +cos^2) +1 + cos sin^2 = cos^2 +1 + cos
or use http://upload.wikimedia.org/math/7/0/7/707415edba7cf845f7fafbf0cc95e23e.png
relation are in: http://en.wikipedia.org/wiki/Cosine#Sine.2C_cosine.2C_and_tangent
a. 2sin^2 = (1) +1 + cos b. 2sin^2 = (sin^2 +cos^2) +1 + cos How did you get from a to b?
This is all so confusing. You know what? Nevermind all this. Thanks for trying to help! Really appreciate it. :)
by this formula: 1=sin^2 +cos^2 and replaced it on 2sin^2 = (1) +1 + cos (replace 1 on the parenthes by 1=sin^2 +cos^2) get 2sin^2 = (sin^2 +cos^2) +1 + cos
some of the relation you can easily obtain by replacing 1 by http://upload.wikimedia.org/math/7/0/7/707415edba7cf845f7fafbf0cc95e23e.png and simplification
another relation obtain: cos(x)+cos(2x)+1=0
okay, yeah I understand that but then in sin^2 = cos^2 +1 + cos how do you add cos^2 + cos?
sorry i will be go, bye
okay, thank you, bye :)
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