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The mole to mole ratio of hydrogen peroxide to oxygen is 2:1. Use this and 5.56 x 10 ^23 molecules of hydrogen peroxide present to determine the liters of oxygen produced at room temp.
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*@RTP= 25.4
ok so just use: n=N/L where : n - moles of atoms/molecules N - number of atoms/molecules L - 6,022 * 10^23 mol-1 and then: n(H2O2)/n(O2) = 2/1 n(H2O2) = 2*n(O2) and then: n=V/Vm V= n*Vm where V - volume n - number of moles Vm - as you wrote 25,4 dm3mol-1
Can you help me through it?
just put numbers in those equations...
For the first one, L, wouldnt it be 6.02 x 10^23?
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yes
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