The number of people in a town of 10,000 who have heard a rumor started by a small group of people is given by the following function: N(t)=10,000/5+1245e^-.97t a. How many people were in the group that started the rumor? b. How many people have heard the rumor after 1 day? After 5 days? c. How long will it be until 1,000 of the people in the town have heard the rumor?
@satellite73 here :)
need help with the last part?
the second and last question
you can do the second one (probably the third too) but the second one is a calculator exercise
what do i put in the calculator?
replace \(t\) by \(1\) you get this http://www.wolframalpha.com/input/?i=10%2C000%2F%285%2B1245e^-.97%29
then replace t by 5 and get this http://www.wolframalpha.com/input/?i=10%2C000%2F%285%2B1245e^%28-.97*5%29%29
so basically for number 1 i should say after 1 day about 21 people heard the rumor?
yes
okay and 678 for after 5 days :) what about the last question?
set that beast equal to 1000 and solve for \(t\)
\[1000=\frac{10000}{5+1245e^{-.97t}}\] \[5+1245e^{-97t}=10\] etc
what would the final answer be in that case?
what would the final answer be in that case?
@satellite73
i got t=-2.1188 but i dont know how to find out the answer from here
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