Question

2^11-4x=8^4x+1

Answer 1

Is that \(2^{11} - 4x = 8^{4x+1}\)?

If so, you will need this:

\(2^{0} = 1\)
\(2^{1} = 2\)
\(2^{2} = 4\)
\(2^{3} = 8\)

Answer 2

Yes that is the problem; how do I use that chart?

Answer 3

Oh wait the -4x is also part of the exponent

Answer 4

Ah. Please use parentheses to clarify meaning.

\(8^{4x+1} = \left(2^{3}\right)^{4x+1} = 2^{3(4x+1)}\)

Can you finish?

Answer 5

That changes everything

Answer 6

\[2^{11-4x}=8^{4x+1} Solve the equation. \]

Answer 7

Now solve \(11-4x = 12x + 3\)

Answer 8

Don't the bases need to be equivalent though?

Answer 9

That's why we MADE them equivalent, using \(8 = 2^{3}\). Thus the chart where we started.