Question

help!!! 2^n+1 x 2^n-4 / 2^2n-2

:(

Answer 1

\[2^{n+1}2^{n-4}=2^{n+1+n-4}=2^{2n-3}\]
next:
\[\frac{2^{2n-3}}{2^{2n-2}}=2^{2n-3-(2n-2)}=2^{-1}\]

Answer 2

@miszery

Answer 3

oh okjay so thanksi need to get used to this website, a bit confusing and can't see everything looks so small

Answer 4

\[\huge\ \frac{2^{2n-3}}{2^{2n-2}}=2^{2n-3-(2n-2)}=2^{-1}\]

Answer 5

^ Now you can see it.

Answer 6

\[\LARGE{\dfrac{2^{n+1}. 2^{n-4}}{2^{2n-2}}}\]use property \(a^b.a^c=a^{b+c}\) in numerator\[\LARGE{2^{n+1+n-4} \over 2^{2n-2}}\]\[\LARGE{2^{n-3} \over 2^{2n-2}}\]now use the property \(a^b/a^c=a^{b-c}\)\[\LARGE{{2^{n-3-2n+2}=?}}\]

Answer 7

thanks for the enlargement it's heaps better :)

Answer 8

ok i got it not thank you... i forgot to change 2n-2 to 2n+2 and got the answer of 2^-5 the first time. cheers :D

Answer 9

yw, buddy :)

Answer 10

do i close this now?

Answer 11

Yeah,Close this up and post a new question in a new thread if you want :)