x+y+z=7 x-y+z=5 x-y-z=-3 solve the system. please show me how to work it out
\[x + y + z = 7 \tag{1}\]\[x - y +z = 5 \tag{2}\]\[x-y-z=-3\tag{3}\]The most effective way to solve is elimination. Add \((1)\) and \((2)\).
right :)))
I don't understand
Not sure how to explain... I think you could use the online resources.
x+y+z=7 x-y+z=5 x-y-z=-3 Let's take 2 equations first. Our goal is to eliminate one variable first. x+y+z=7 x-y+z=5 Make z the subject for the first one. z = 7 - y -x
Once you have this, substitute this value of "z" in second equation. x-y+z=5 <-2 x - y + (7-y-x) = 5 Do you agree till here?
ok yea
Simplify the new equation. x - y + (7-y-x) = 5 x - y + 7 -y -x = 5 -2y + 7 = 5 -2y = 5 - 7 y = -2/ -2 y = 1 Agree?
ok yeah
Now again take 2 equation. Let's take the last two now. x+y+z=7 x-y-z=-3 Solve the first one for x. x = 7 -z - y Substitute this value in the second one. x - y - z = -3 (7-z-y) -y-z =-3 Afer simplification we get -2y -2z = -10
We already knew the value of y. Which was 1. -2(1) -2z = -10
ok..
Now solve for z to get it's value.
Finally you'll have the value of y and z. Substitute it in any equation to get the value of x.
2,1,4 ?
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http://fc07.deviantart.net/fs71/f/2011/337/2/3/like_a_boss_by_mrfletch1000-d4i37i2.jpg
thanks so much
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