Question

Solve the quadratic equation.
2x2 + 35 = 17x

Answer 1

answer choices


A)
7/2and 5

B)
-7\2and 5
C)
-7\2and -5
D)
2/7and 1/5

Answer 2

2x^2+35-17x=0
now divide the equation by the coefficient of x^2
\(\LARGE{{2x^2+35-17x \over 2}=\dfrac{0}{2}}\)
\(\LARGE{x^2+\dfrac{35}{2}-\dfrac{17x}{2}=0}\)
\(\LARGE{x^2+({-17/2}) \space x=-35/2}\)

Answer 3

There are three methods we can implement.

1) Using the quad formula

2)breaking the middle term

3)Completing the square method.

Answer 4

For Using The Quad formula you would have to compare your equation with the standard equation.

Which is,

\[\huge\ ax^2+bx+c=0\]

And determine a,b and c.

Answer 5

\[x^2-\dfrac{17}{2}x +\left( 17 \over 4 \right)^2={-35 \over 2}+\left( 17 \over 4 \right)^2\]

Answer 6

Then Using the Quad formula,

\[\huge\ x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]


@jiteshmeghwal9 has showed completing the square method.

Answer 7

\[(x+\dfrac{17}{4})^2={-35 \over 2}+\dfrac{289}{16}\]

Answer 8

Now can u do it further @Pookiieluvzyhu ??

Answer 9

Looks like @jazy is gonna take a day lol :P

Answer 10

yea yea..kk thanks...let me read over what yall said.it was alot lollz.. thanks @jiteshmeghwal9 @hba @jazy

Answer 11

yw :)

Answer 12

Well, you could use the Quad formula.

Quadratic equation - \[ax^2 + bx + c\]You have...\[2x^2 - 17x + 35\] a = 2
b = -17
c = 35

Quadratic Formula.\[\frac{ -b \pm \sqrt{b^2 - 4ac} }{2a }\]Plug in the values.\[\frac{ 17 \pm \sqrt{49 - 4(2)(35)}}{ 2(2) } \]Solve.

Answer 13

Welcome :)

Answer 14

Wow that took a longgggg time to post O_O

Answer 15

Welcome if it helps lol. (: