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Linear Algebra 7 Online
OpenStudy (anonymous):

y=2x-5 then put it to a graph then a table and draw the line

OpenStudy (ryan123345):

on the y axis ( the line that goes up and down ) put a dot at -5 then go up 2 and right one then put the dot. Then connect the lines.

OpenStudy (anonymous):

x|y -2|9 -1|7 0|5 1|3 2|1 3|-1 4|-3 plot each of these points on the xy-graph and draw a line connecting each point in a straight line.

OpenStudy (anonymous):

those are some points that will lie on the line.

OpenStudy (anonymous):

Omg thank you so much!! i might need help on more things on the back of the paper and in the future

OpenStudy (anonymous):

NP,just hmu if you do.

OpenStudy (anonymous):

alright ill do that

OpenStudy (anonymous):

Easier way. First make one point on the y-axis at -5 (this is your y-intercept). Then, from that point, move one unit right and two units up because your slope is 2 (or it can be depicted as 2/1). Slope is rise over run, so you move ONE digit right (the denominator) and TWO digits up (the numerator). Make a point there. Join the two points. That's your line!

OpenStudy (ryan123345):

I think we get it...

OpenStudy (anonymous):

The first thing you should do is make up so x-coordinates in your table Now I need to use the equation to find the y-coordinates. This is done by substituting the x-coordinates into the equation: First: x = -2 y = -2x + 5 y = -2*(-2) + 5 y = 4 + 5 y = 9 x --> -2, -1, 0, 1, 2 y --> 9, _, _, _, _ second: x = -1 y = -2x + 5 y = -2*(-1) + 5 y = 2 + 5 y = 7 x --> -2, -1, 0, 1, 2 y --> 9, 7,5, 3, 1 the y values are going down by 2. (this is because of the -2 in front of the 'x' in the equation) So the table of values: x --> -2, -1, 0, 1, 2 y --> 9, 7, 5, 3, 1

OpenStudy (ryan123345):

Thumbs up? :3 @colombianpride12 @Clayman

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