Question

Let f(x) = x^3 + 4x^2 − 1. Show that f(x) has a root between 0 and 1.

Answer 1

Calculus?
Can you evaluate at x=0, then at x=1, and claim that because the function is continuous, it must attain every value in between?

Answer 2

can you solve this with IVT

Answer 3

for show that a function have a root between a and b, you must have:
f(a)*f(b)<0

ok?

Answer 4

IVT? Initial value theorem? I don't believe it applies.

Answer 5

i dont know what is IVT
IVP=Initial value Promblem

Answer 6

@mahserindortatlisi can you solve?

Answer 7

intermediate value theorem.are u a real math lecturer it is unbelievable :S

Answer 8

I'm a real math teacher, not a lecturer, and IVT is an acronym with many meanings.

Answer 9

Intermediate value theorem is the method I described to you initially. Since the function is negative at x=0 and positive at x=1, and the function is continuous over the interval, there is some x such that 0 < x <1 and f(x) = 0.

Answer 10

my English is not good bay the way you can see i explain it in my first post