* i need help asap* do i use the combined gas law for this problem?
If 29 L of methane, CH4, undergoes complete combustion at .961 atm and 413 K, how many liters of each product would be present at the same temperature and pressure? If i dont use this law, how do i solve it?

Question

* i need help asap* do i use the combined gas law for this problem?
 If 29 L of methane, CH4, undergoes complete combustion at .961 atm and 413 K, how many liters of each product would be present at the same temperature and pressure? If i dont use this law, how do i solve it?

abb0t · Answer

Well, combustion means that you are adding heat to produce (what is known as combustion), carbon dioxide and water. For this, I am going to suggest you use the formula: PV = nRT
p = presure (usually in units of atm or mmHg)
v = volume (L)
n = moles 
R = constant which can be found in your chemistry book or online
T = temperature (K)

Using algebra, you can rearrange the formula to find whatever you are being asked for.
It might be useful to write down the stoichiometric equation first.