Question

Find the derivative: y= sin(cos(2x))

Answer 1

Use the chain rule. The derivative of the outside times the derivative of the inside.

Answer 2

OK

Answer 3

-sin(2) * sin?

Answer 4

Hence, you want to find f' of sin first, then multiply it by the derivative of cos (the inside), and so forth with the 2x.

Answer 5

So, sin(2x) = -cos2 right?

Answer 6

You keep the (inside) you keep, you are sort of treating it as a constant. For example:
\[\sin(x-p+y^{zt}-\frac{ \sqrt{s} }{ M }) \]

then f' is: \[\cos(x-p+y^{zt}-\frac{ \sqrt{s} }{ M }) \times \frac{ d }{ dx }[(x-p+y^{zt}-\frac{ \sqrt{s} }{ M })]\]

Answer 7

Understood, thanks!