Question

Find mBAC in circle O. (The figure is not drawn to scale.)

Answer 1

A. 170

B. 95

C. 47.5

D. 42.5

Answer 2

do u go to connexus

Answer 3

no i go to James Madison

Answer 4

i was on the unit 6 test and was wondering if someone could help me with some problems

Answer 5

im on exam 6 test to

Answer 6

Oh, hey. Real simple. If you can figure out the measure of the arc that the inscribed angle subtends, then the angle will simply be:
\[\Large \text{inscribed angle} = \frac{\text{measure of arc subtended}}{2}\]

Answer 7

i dont know how to figure that out the arc -_-

Answer 8

so it would be 85 .. then what do you do? can you show me

Answer 9

naw gurl. it aint even.

Answer 10

im confused ...

Answer 11

I can tell.

Answer 12

Helppp lol

Answer 13

would it be 90? 95? I dont know lol

Answer 14

I'm sorry. The whole guessing business just kills me. Stop guessing, stop begging for answers, and show some effort.

Answer 15

i am i dont know how to do this, Im trying ..

Answer 16

All of the facts you need:

Two angles that form a straight line must add up to 180 degrees.
An arc has the same measure as a central angle that includes it.
An inscribed angle is half of the measure of the arc it includes.

Answer 17

@ErinWeeks We should never guess in math, or else you will always have 25% or thereabouts for your grades! :(
The above diagram shows the relation between the angles subtended by the same chord AC, at the circumference B or at the centre O.

If you join OB, then OA,OB,OC are all equal to the radius. Thus triangl OAB is isosceles, therefore mBAO=mABO. Similarly mBCO=mCBO.
But mABO+mCBO=mAOC (exterior angles), which means finally
\( mAOC=2 * mABC.\)

Hope this helps.
Note: this is similar to the question I answered previously. Hope that this more detailed explanation helps you work on other problems.
Please, do NOT guess your answers if you want a good grade. Understanding is faster than guessing.