Question

CAN SOMEONE PLEASE HELP ME WITH #13-14

Answer 1

Think of sqrt of 5 as raising something to the 1/5th power. You would then get... (y^3) (32^(1/5))(x^(4/5)) minus (7)(x^(4/5))(y^3)

Answer 2

Factor out Y^3 and x^(4/5) and you get (y^3)(x^(4/5)) times (32^(1/5) - 7).

Answer 3

since 2^5 is 32, 32^(1/5) = 2, giving (2-7) (y^3)(x^(4/5)) or -5((y^3)(x^(4/5))

Answer 4

Hope all that makes sense, it's hard typing these things out