Question

What is the equation of the line that passes through the point (4, 1) and has a slope of 5?

Answer 1

@cammyabbo can you help me with this ?

Answer 2

hi, yes i think so

Answer 3

so we know we can set our midpoint equation equal to the (4,1)

Answer 4

Try to help yourself first by telling us what you would try first.

Answer 5

y = 5x - 3
y = 5x - 1
y = 5x + 3
y = 5x - 19
those are the options

Answer 6

Y=mx+b......m is our slope and b is our y intercept

Answer 7

we know our slope is 5

Answer 8

so, so far the equation is y=5x

Answer 9

Not, quite. So far the equation is $$y=5x +b$$

Answer 10

right

Answer 11

ok so whats the next step ?

Answer 12

you know the line passes through (4,1)

Answer 13

so 1=5(4)+b

Answer 14

1=20+b

Answer 15

your y-int is -19

Answer 16

thats one of the options :)

Answer 17

the equation of your line is y=5x-19

Answer 18

so its the last one?

Answer 19

all you did was plug (4,1) in the standard y=mx+b equation

Answer 20

yes

Answer 21

thank you sooooo much !!

Answer 22

my pleasure

Answer 23

Another way to do it is to use y-y1=m(x-x1) with m being your slope. This is just point slope form, so it's the same thing. You'd get y-1=5(x-4) so you'd have y-1=5x-20 and then y=5x-19. Not saying either way is better, but just in case you want this form too, that's it. :)