Question

4(z − 3) ≤ 3(z + 5) write as an interval notation... I got that x=27

Answer 1

Keep in mind that there is a ≤ sign and not a = sign

Answer 2

IF the equation was

4(z − 3) = 3(z + 5)

then you would be correct in saying that the answer is x = 27

Answer 3

but how do I write that in interval notation.

Answer 4

You first have to figure out if it's x <= 27 or x >= 27

Answer 5

So use the same techniques you used to solve the equation, but keep the inequality sign

Answer 6

did you mean negative infinity?

Answer 7

YES...OH THANK YOU

Answer 8

I have a few more like this that I sure could use coaching on. I am still shaky on the subject...so if you would be willing to hang with me here for a little bit for some support, I truly would appreciate it

Answer 9

sure i can answer a few more

Answer 10

\[2x-8>-2\] .... I came up with -3... would I write it as [-3.00)

Answer 11

keep the inequality sign and flip it if you multiply/divide both sides by a negative number

2x - 8 > -2

2x > -2+8

2x > 6

x > 6/2

x > 3

So it should be (3, infinity)

If there is a line under the inequality sign, then it is [3, infinity)

Answer 12

Let me see if I understand this... if it is a definitive > without the hashtag under it... the answer is a ( whereas the > with the hashtag under it, it is a [

Answer 13

that is correct, by hashtag you mean underline

I've never heard of "hashtag" being used in this context, but underline sounds more appropriate here

Answer 14

you are correct.. I just couldn't think of the word.. this math has me frazzled... That said... does this next problem make any sense to you... h = 48t + 1/2 at^2

Answer 15

what do you want to do with it?

Answer 16

solve the formula for a specified variable... for 'a'

Answer 17

The idea is to isolate 'a'

so we must first subtract 48t from both sides

then multiply both sides by 2

finally, we divide both sides by t^2 to isolate 'a'

Answer 18

\[\Large h = 48t + \frac{1}{2}at^2\]


\[\Large h - 48t = \frac{1}{2}at^2\]


\[\Large 2(h - 48t) = at^2\]


\[\Large \frac{2(h - 48t)}{t^2} = a\]


\[\Large a = \frac{2(h - 48t)}{t^2}\]

Answer 19

HOLY GOD... what is THAT???

Answer 20

the steps in solving for 'a'

Answer 21

I understand that... but the mere sight of that is intimidating...