Question

If cosθ + cos^(2) θ = 1, then sin^(12) θ + 3 sin^(10) θ + 3 sin^(8) θ+ sin^(6) θ + 2 sin^(4) θ + 2 sin^(2) θ – 2 =

Answer 1

Your clue is:
\[\cos{\theta} + \cos^2{\theta}= 1\]
\[\cos{\theta}=\sin^2{\theta}\]

Answer 2

but i have solved it my answer is not cmg

Answer 3

answer optios are:
(A) 0
(B) 1
(C) 2
(D) 3

Answer 4

Show me your working.

Answer 5

plse see the attachment and when i put the value , i got -5 / 64 answer

Answer 6

You mixed up something in the middle.

Answer 7

\[\sin^2{\theta}=\sqrt{1-\sin^2{\theta}}\]

Answer 8

kk

Answer 9

but at the end , i m not getting it

Answer 10

Is that equation equal to 0?

Answer 11

no

Answer 12

i don't know

Answer 13

i have to calculate the value of sin^(12) θ + 3 sin^(10) θ + 3 sin^(8) θ+ sin^(6) θ + 2 sin^(4) θ + 2 sin^(2) θ – 2
the option are
(A) 0
(B) 1
(C) 2
(D) 3

Answer 14

What specific topic is this question in?

Answer 15

it is the topic of polynmials

Answer 16

at the end i don't get the answer

Answer 17

\[\cos^6{\theta}+3\cos^5{\theta}+3\cos^4{\theta}+\cos^3{\theta}+2\cos^2{\theta}\]

Answer 18

you have sum up the equation

Answer 19

i m really stuck in this question