Question

Simplify the sum.

Answer 1

\[4 \over m + 9\]\[+\]\[5 \over m^2 - 81\]

Answer 2

add the tops right = 9

Answer 3

\[\dfrac{4}{m+9}+\dfrac{5}{m^2-81}\]\[\dfrac{4(m^2-81)+5(m+9)}{(m+9)(m^2-81)}\]\[4(m+9)(m-9)+5(m+9) \over (m+9)(m+9)(m-9)\]Take \(m+9\) common in both numerator & denominator\[\cancel {m+9}[4(m-9)-5] \over \cancel {m+9}[(m+9)(m-9)]\]

Answer 4

\[{4m-36-5 \over m^2-81}?\]

Answer 5

im confused i have answer choices and that is none of them i tried my best and got the wrong answer

Answer 6

@jiteshmeghwal9

Answer 7

4m-(36+5)
solve the brackets first

Answer 8

\[a. 9 \over (m -9)(m + 9)\]

Answer 9

this is what i got when i tried again

Answer 10

4m-36-5=4m-41

Answer 11

put 4m-41 instead a.9

Answer 12

im saying thats my answer which is choice a

Answer 13

\[4m-41 \over (m-9)(m+9)\]is this ur answer ?

Answer 14

thats what i got yes, my second answer

Answer 15

ok ! @ash2326 m i correct ?

Answer 16

???????

Answer 17

A small mistake
\[\frac{4}{m+9}+\frac 5 {m^2-81}\]
LCM of m+9 and m^2-81 is m^2-81
\[\frac{4\times (m-9)}{(m+9)(m-9)}+\frac 5 {m^2-81}\]
\[\frac{4\times (m-9)+5}{(m+9)(m-9)}\]
\[\frac{4m-36+5}{m^2-81}\]
\[\frac{4m-31}{m^2-81}\]

Answer 18

Ohh ! ok sorry :P

Answer 19

Gt it @jennyjewell25 ?

Answer 20

im sorry i still dont understand

Answer 21

i guess my answer was wrong not sure

Answer 22

@Hero