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Factor. 8 + 7y - y^2
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(y-8)(y+1)
That's only when you move everything to the otherside when you make that equation equal to zero.
\[(8-y)(1+y)\]
Looks the same but you don't get the -y^2
Definitely not the same, but @Azteck is right.
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And when you expand @musiclover101 's factored equation, you will get y^2-7y-8 instead of your above equation.
sorry -(y-8)(y+1)
So when you put it on the other side it turns to y^2 - 7y - 8? How does it do this again? I forgot.
When you take out the minus sign.
-(y^2-7y-8)
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Oh alright, thank you!
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