Express as a single logarithm:
2 log (x-1) + 4 log (x^2+1) - 3 log (x+2)

Question

Express as a single logarithm:
2 log (x-1) + 4 log (x^2+1) - 3 log (x+2)

hartnn · Answer

you only need 2 log formulas here : 
$\log A+\log B=\log(A+B) \ \log A^B=B \log A$
try using them....

hartnn · Answer

example $7\log (x+9) =\log  (x+9)^7$

hartnn · Answer

so, what about 2 log (x-1) =... ?

anonymous · Answer

log (x-1)^2

anonymous · Answer

right?

hartnn · Answer

yes, now how about 
 4 log (x^2+1) =.. ?

hartnn · Answer

and 3 log (x+2)= ... ?

hartnn · Answer

its the same way you solved  2 log (x-1)

anonymous · Answer

I'm sorry for being late.

hartnn · Answer

no problem,. you can try now :)

anonymous · Answer

ah! and the answer for my question would be log [(x-1)^2+(x^2+1)^4]/(x+2)^3

hartnn · Answer

is there a + sign in between ? there shouldn't be
if it looks like : 
$\huge \log \frac{(x-1)^2(x^2+1)^4}{(x+2)^3}$
then its correct...

anonymous · Answer

ah!! thank you! I remembered.. that if there's a +, that means it should be multiplied. right?

hartnn · Answer

yes, + sign before log, means multiplication after log.

anonymous · Answer

oh ok! thanks! I'm really bad at logarithms. Can you help me with another one?

hartnn · Answer

sure, but post it as a new question, if i can't help, someone will durely help :)

anonymous · Answer

wait, it's embarrassing to always post a new question about logarithms. O.o I think you can help me with this.

anonymous · Answer

Solve for x: $$\log_{2} (x-4)  \log_{2} (x-3)=1 $$