Question

What is the value of p?
x=-1/8(y^2)
i don't understand this because there is no p in the equation

Answer 1

it can be peak. if it is, answer is (0,0). but i'm not sure :)

Answer 2

p?
stands for

Answer 3

the vertex is at (0,0) i got this
does this make sense to you? i dont know if my work is right

a=-1/8, 1/4p
-1/8=1/4p
-4p=8
p=-2

Answer 4

i'm not sure what it stands for.. it doesnt say

Answer 5

no! why 1/4p=-1/8?!?

Answer 6

i found that solution online

Answer 7

http://answers.yahoo.com/question/index?qid=20120108134800AAPbXdZ

Answer 8

\[y ^{2}=-8x\]
\[y ^{^{2}}=4(-2)x\]
\[y ^{2}=4ax\]
a=-2

Answer 9

of if u treat it as \[y ^{2}=-4ax\] then a=2

Answer 10

i see

Answer 11

it can be true. i don't know.

Answer 12

thanks :) can one of you please help me find the length of the focal width for the same equation? x=-1/8(y^2)

Answer 13

@marsss @nitz

Answer 14

ya
can u please wait a sec

Answer 15

you should plug x=-2 and x=2 in equaiton and then find the difference

Answer 16

sure thanks :) @nitz

Answer 17

welcome :)

Answer 18

ill try plugging in x one minute

Answer 19

when x=2 y=4i,-4i

Answer 20

when x=y=4,-4

Answer 21

@marsss what is the diff

Answer 22

difference*

Answer 23

length is 4a

Answer 24

i'm sorry i had a mistake. x does'nt equal 2. when x=2, difference is 4-(-4)=8 ok??

Answer 25

ok

Answer 26

hey a and p are one and the same thing....just notational difference

Answer 27

oh ok, so what would the fi

Answer 28

final answer be in this case

Answer 29

@nitz

Answer 30

i dont know how to find it from here

Answer 31

length is 8

Answer 32

thank you so much :)