Question

the equation of the line tangent to the graph of y= tan(x)+3 at the point (0,3) is:

Answer 1

If you take the derivative of y = tan (x) + 3 you get:

y' = sec^2 (x)

and the value at x = 0 is y' = 1, so that is your slope.

Using the slope-intercept form for the equation of a line:

y = mx + b

we get:

y = (1)x + 3

or

y = x + 3

Answer 2

Here's a graph of the original equation and of the line:

Answer 3

All good now?

Answer 4

yep thanks

Answer 5

Good luck in all of your studies and thx for the recognition! @zombiejr