11. Use natural logarithms to solve the equation. Round to the nearest thousandth.

3e2x + 4 = 24 help!!

Question

11.   Use natural logarithms to solve the equation. Round to the nearest thousandth.

3e2x + 4 = 24  help!!

whpalmer4 · Answer

$$3e^{2x}+4=24$$?

anonymous · Answer

subtract 4
divide by 3
take the log
divide by 2

anonymous · Answer

when you take the log, use a calculator

whpalmer4 · Answer

$$3e^{2x}+4=24$$
$$3e^{2x}=20$$$$e^{2x}=\frac{20}{3}$$Take natural log of both sides to get rid of e^{2x}$$2x=\ln{\frac{20}{3}}$$$$x=\frac{1}{2}\ln{\frac{20}{3}}$$

whpalmer4 · Answer

@satellite73 's steps are exactly right, just illustrating them so you can see why it works

anonymous · Answer

–0.960
0.499
1.117
0.949
 but i dont get these answers?

whpalmer4 · Answer

What do you get for the natural log of (20/3)?

whpalmer4 · Answer

Are you perhaps getting 0.823...?  That's log base 10

anonymous · Answer

i got 6.666637..

whpalmer4 · Answer

Okay, 20/3 = 6.6666666...  Now take the natural logarithm of that, and you should get 1.897... divide that by 2 and you get?

anonymous · Answer

.9485