Question

so if it was t^8 (t^10)^0 thats t^8and t^10
I would add 8 and 10 so its t^18? am i right?

Answer 1

no

Answer 2

its t^80

Answer 3

any number to the power of zero is 1

Answer 4

\((t^8)^0=1\)

Answer 5

1x10=10 and 10x8= 80?

Answer 6

you are raising \(t^8\) to the power of zero, not to the power of one

Answer 7

\((t^8)^0=t^{8\times 0}=t^0=1\)

Answer 8

thats for the 10 i think

Answer 9

in general \(b^0=1\) for any number \(b\) (unless \(b=0\) but that is a different story)

Answer 10

my fault, but same idea

Answer 11

\((t^{10})^0=t^0=1\)

Answer 12

so its just t^8?

Answer 13

to you are left with
\[t^8\times t^0=t^8\times 1=t^8\]

Answer 14

yes, it is \(t^8\) you are right

Answer 15

Think of it like t^2 = t*t, so t^1 = t*t/t = t and t^0 = t*t/(t*t) = 1

Answer 16

thxs you all