Question

What is the square root of minus 1.
When i do it in a scientific calculator, it says 'i' (imaginary unit) and i have no idea what that means

Answer 1

\[\sqrt{-1} = x \] what is the value of x

Answer 2

please dont put links

Answer 3

Imaginary numbers result when you are taking the square root of any negative number:
For an example, \[\sqrt{-1}\] = i
\[\sqrt{-25} = 5i\]
The 'i' is kind of like the negative sign

Answer 4

so what is an imaginary unit

Answer 5

I know of a video you can watch if you want to

Answer 6

yes what is the vid @zaynahf

Answer 7

did you see the link @awn786

It has everything.

Answer 8

yes i did but what is an imaganary unit

Answer 9

1) http://www.youtube.com/watch?v=Iv_uzy4_gec

2) https://www.khanacademy.org/math/algebra/complex-numbers/complex_numbers/v/algebra-ii--imaginary-and-complex-numbers?v=C-2Ln0pK3kY

Answer 10

WOW OMG complicated @hba

Answer 11

The first link is really straight forward, try that

Answer 12

@awn786 Well,I tried to simplify and put everything :)

Answer 13

thanks for trying. @hba

Answer 14

You are welcome :)

Answer 15

listen and can u give a simple i word answer: \[\sqrt{-1}=x\] what is the value of x in numbers.

Answer 16

1 word answer*

Answer 17

not i word

Answer 18

I can help you understand what imaginary numbers are.

So,the base of imaginary numbers is actually laid upon some of the things like

\[\huge \ i=\sqrt{-1}\]

The other thing is

\[\huge\ \omega=\frac{ -1+i \sqrt{3} }{ 2 }\]

Answer 19

whats w

Answer 20

We call this omega,It's derivations is given in my link :)

Answer 21

whats w @hba

Answer 22

Now as per your question.

x=root{-1}

x=i

Here i is actually iota and it is an imaginary number.

Answer 23

That's omega @awn786

Answer 24

whats omega

Answer 25

@awn786 Please check the link i have provided.

It has everything

Please give it a read.

Answer 26

i said in numbers. your answer is basicly my question

Answer 27

Well,In numbers it is sqrt{-1}

Answer 28

it should be easy shouldent it.

Answer 29

i dont understand ur link

Answer 30

what is omega

Answer 31

I have already told you what omega is.

Answer 32

no u havent @hba

Answer 33

I said it is -1+i sqrt{3}/2

Answer 34

ok (i dont get it but ok) i' only in year 9 doing my gcse's

Answer 35

\[\sqrt{-1}\] doesn't exist as a the REAL number you are asking for, because there's no number that you can square (because of the SQUARE root) and gives you -1

Answer 36

you just need to know what a square root is

Answer 37

i know what a square root is ofc

Answer 38

that's why there's no sqrt of ANY negative numbers, because everthing squared is BIGGER than 0

Answer 39

(possitive)

Answer 40

oh i get it so its an imaganary number because it cant exist?

Answer 41

you have the best responce

Answer 42

EXACTLY, it CAN'T EXIST as a "normal number"

Answer 43

thank u so much.

Answer 44

^^^^^^ @GCR92

Answer 45

so mathematicians around XVII century had to figure out another type of numbers, called COMPLEX numbers, and the first number of complex numbers is \[\sqrt{-1}\]

Answer 46

they INVENTED it

Answer 47

you are welcome

Answer 48

ur a genius @GCR92

Answer 49

not really, but thanks!

Answer 50

ill draw you something

Answer 51

you can bring the most complex thing and make others understand. are u sure ur not related to prfsr.
brian cox