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They have a common denominator, that's nice.
Try factoring the top one.
alright hold up a sec
t(1t+6) or somethin like that
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nope
First you should subtract the fractions to get: \[ \frac{t^2+6t-7}{t-1} \]
Then factor \[ t^2+6t-7 \]
t(-1+-6)
not quite, but close
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yea thats what i meant to say
\((t-1)(t+7)\)
so thts the simplified answer
\[ \frac{(t-1)(t+7)}{t-1} \]We have to divide.
so would the t-1 cancel each other
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yes
alright thanks
so the answer is (t+7)
yes
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