Question

Help Needed

Answer 1

ok. Let the mass of the particle be m.
Net force acting on a particle can be written as :
\[F = \frac{ dP }{ dt }\]
where P is the momentum of the particle.
Therefore, dP = Fdt
\[\int\limits_{Po}^{P} dP = \int\limits_{0}^{t}Fdt\]
Therfore,
\[P2 - P1 = \int\limits_{0}^{t}Fdt\]
Which means, change in momentum = area under the Force vs. Time graph.
From the given graph, area under the graph =
\[(\frac{ 1 }{ 2 } * 3 * 8) + (3*8) + (\frac{ 1 }{ 2 }*3*8) = 48Ns\]

initial momentum = mv = m*(-4.4) = -4.4m kgm/s
Let final velocity be V.
Therefore, final momentum = mV
Therefore change in momentum = mV - (-4.4m) = m(V+4.4) kgm/s

equating,

m(V+4.4) = 48

If we know the mass of the particle, we can calculate its final velocity using this equation. If mass is not known, we cannot determine the final velocity

Answer 2

Oh, mass is known, It was reminded in previous question. Thanks.