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Physics 8 Online
OpenStudy (anonymous):

A car weighing 1400kg accelerates from 90 km/hr to 110 km/hr in 6.0s. a) assuming no friction, what was the power output of the car? b) If a frictional force of 700 N acted on the car over a distance of 400 m during the same 6.0-second acceleration, what would be the power output of the car if the same speed increase was observed?

OpenStudy (anonymous):

Figure out it's change in kinetic energy.

OpenStudy (anonymous):

You have the mass and two velocities. So calculate the kinetic energy before and after acceleration.

OpenStudy (anonymous):

Power is just going to be energy / time

OpenStudy (anonymous):

kinetic energy is 1/2 mass * velocity^2

OpenStudy (anonymous):

You probably want to convert units to m/s

OpenStudy (anonymous):

Multiply by 1000 and divide by 3600?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

For b) " 700 N acted on the car over a distance of 400 m" Just remember that work = force * distance that will tell you how much energy was taken away

OpenStudy (anonymous):

so subtract that out and calculate the power again.

OpenStudy (anonymous):

@applesjgtl got it?

OpenStudy (anonymous):

For part a, what value do I use for energy? Is it KE2-KE1?

OpenStudy (anonymous):

@wio, still there?

OpenStudy (anonymous):

For part a) use energy

OpenStudy (anonymous):

then divide the change in energy by time to get power output.

OpenStudy (anonymous):

Here's what I have

OpenStudy (anonymous):

Oh, I get it. Thanks for your help!

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