(systems) what is the solution to the following system?
y=1/2x+3
x=15-y

Question

(systems) what is the solution to the following system?
y=1/2x+3
x=15-y

anonymous · Answer

Re-writing it $$y=\frac{ 1 }{ 2 }x+3$$ $$x=15-y$$

anonymous · Answer

You can use substitution, from the first equation y is equal to (1/2)x+3

so you can take that and plug it into the second equation where y is

x=15-(1/2)x+3

now solve for x

anonymous · Answer

So all i do is solve for x and y and then im done?

chihiroasleaf · Answer

yes.., to find the solution, you need to find the x and y ...

you have y = (1/2) x + 3 
and 
x = 15 - y

if you want to use substitution method, substitute the first equation into the second equation 
so, you'll have
x = 15 - { (1/2)x + 3}

what is x?

anonymous · Answer

im a little stuck. I distributed the negative so i got x=15-1/2x-3 then i continue and get x=12-1/2x i have i done it right so far? and how do i continue?

nottim · Answer

what you need how to continue?

nottim · Answer

gotta be more sure of yourself, thats for sure

anonymous · Answer

@NotTim what do you mean? uh.. i kinda need some help on this were not  all geniuses

nottim · Answer

well...add likes to likes really.